第1879题：展开多项式
利用泰勒中值定理，按 (x+1)(x+1)(x+1) 的乘幂展开多项式 1+3x+5x2−2x31+3x+5x^2-2x^31+3x+5x2−2x3 ，得到( ).
A. 7+7(x+1)7+7(x+1)7+7(x+1) −2(x+1)2−2(x+1)3-2(x+1)^2-2(x+1)^3−2(x+1)2−2(x+1)3
B. 7+7(x−1)7+7(x-1)7+7(x−1) −2(x−1)2−2(x−1)3-2(x-1)^2-2(x-1)^3−2(x−1)2−2(x−1)3
C. 5−13(x+1)5-13(x+1)5−13(x+1) +11(x+1)2−2(x+1)3+11(x+1)^2-2(x+1)^3+11(x+1)2−2(x+1)3
D. 5−13(x−1)5-13(x-1)5−13(x−1) +11(x−1)2−2(x−1)3+11(x-1)^2-2(x-1)^3+11(x−1)2−2(x−1)3
安卓手机扫描二维码安装App
苹果手机扫描二维码安装App