第197题：汤姆约分法

汤姆在82题时发现了两位数的巧合：

$\dfrac{16}{64}$ $=\dfrac{1 \bcancel{6}}{\bcancel{6} 4}$ $=\dfrac{1}{4}$

$\dfrac{26}{65}$ $=\dfrac{2 \bcancel{6}}{\bcancel{6} 5}$ $=\dfrac{2}{5}$

$\dfrac{19}{95}$ $=\dfrac{1 \bcancel{9}}{\bcancel{9} 5}$ $=\dfrac{1}{5}$

现在他又发现几个三位数的巧合：

$\dfrac{199}{995}$ $=\dfrac{1 \bcancel{9} \bcancel{9}}{\bcancel{9} \bcancel{9} 5}$ $=\dfrac{1}{5}$

$\dfrac{266}{665}$ $=\dfrac{1 \bcancel{6} \bcancel{6}}{\bcancel{6} \bcancel{6} 5}$ $=\dfrac{2}{5}$

$\dfrac{124}{217}$ $=\dfrac{\bcancel{1} \bcancel{2} 4}{\bcancel{2} \bcancel{1} 7}$ $=\dfrac{4}{7}$

$\dfrac{127}{762}$ $=\dfrac{1 \bcancel{2} \bcancel{7}}{\bcancel{7} 6 \bcancel{2} }$ $=\dfrac{1}{6}$

那么，请你算算，$\dfrac{499}{998}$ 、$\dfrac{26666}{66665}$ 、$\dfrac{19999}{99995}$ 也有此巧合吗?