安卓手机扫描二维码安装App

第866题:建立方程求解



a,b,ca,b,c 都是已知数,且


a+b+c=3a+b+c=3


a(1b+1c)a(\dfrac{1}{b}+\dfrac{1}{c}) +b(1c+1a)+ b(\dfrac{1}{c}+\dfrac{1}{a}) +c(1a+1b)+c(\dfrac{1}{a}+\dfrac{1}{b})=3 =3


那么


1a+1b+1c \dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c} =?=?




本题有提示.
苹果手机扫描二维码安装App
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