安卓手机扫描二维码安装App

第835题:指数式的计算



已知  


a12a^{\frac{1}{2}}++a12a^{-\frac{1}{2}}=3=3 (a>0)(a>0)


a32a32a12a12\dfrac{a^{\frac{3}{2}} - a^{-\frac{3}{2}}}{a^{\frac{1}{2}} - a^{-\frac{1}{2}}} 的值.




a32+b32a^{\frac{3}{2}} + b^{\frac{3}{2}} =(a12+b12)=(a^{\frac{1}{2}} + b^{\frac{1}{2}})(aa12b12+b)(a- a^{\frac{1}{2}} b^{\frac{1}{2}} +b), (a>0,b>0)(a>0,b>0)
a32b32a^{\frac{3}{2}} - b^{\frac{3}{2}} =(a12b12)=(a^{\frac{1}{2}} - b^{\frac{1}{2}})(a+a12b12+b)(a+ a^{\frac{1}{2}} b^{\frac{1}{2}} +b), (a>0,b>0)(a>0,b>0)
苹果手机扫描二维码安装App
我来回答